Which of the following reactions are correct? Copper(I)-Bipyridyl Complex Question 68. Among the following amines’ the strongest Bronsted base is Heating alkyl halide with primary, secondary and tertiary amine can be prepared by reduction of LiAlH4 followed by treatment with water. (d) Acylation of aniline N 2 +Cl-Cu/HCl Cl + N 2 Benzene diazonium Chloride N 2 Cl + - Cu/HBr Br + N 2 common of these is the Ullmann Ether Synthesis. (c) Diazotisation of aniline Assertion (A): Acetanilide is less basic than aniline. Therefore, activating effect of —NHCOCH3 group is less than that of —NH2 group. (a) aromatic oxime (b) aromatic hydrocarbon Oxalic Diamides and tert-Butoxide: Two Types of Ligands Enabling Practical Solution: (a) Due to delocalization of lone pair of electrons on the N-atom into the benzene ring, C6H5NH2 is the weakest base. (a) excess H2 Question 44. Question 53. Enables Cu-Catalyzed Aryl Amination with High Turnovers (a) H2 (excess)/Pt    (b) LiAlH4 in ether Question 48. Solution: HNO3 acts as a base in the nitrating mixture (HNO3 + H2SO4) and provides the electrophile. (d) Both Assertion and Reason are correct and Reason is the correct explanation of Assertion. Another possibility is the use of Cu(I) for the oxidative coupling of x��\Ks#In�Y��:9HO�6ߏ��aF�ay�m��bo�C�G��Ѧ����>����Y�E�j�:&�U �B"������S�VO��mrV�vZ'�k����j����_6��?�_��;��x���ݦ�������sA��3}2�q}���T�C�>��pӎI��D�����M������.�I���ި�sw��?Ϻ�_��t��^z/T��v���˽3���O$��i�)�w�G�}&�0�Ph`2=_���V2c��?��Li��c��z�[���ԧ�~��}�uǹ��L~{x�Wh�f�9c�9�cof���ݢΚ���$ͨm���"���r�(�55\��h��h�/�n�r��e���lY���\�����X~�B�����)}���c��>����T�/��B:� �z댡���u= Reduction of aromatic nitro compounds using Fe and HCl gives . Solution: (c). Copper-Catalyzed Coupling of Alkylamines and Aryl Iodides: An Efficient System The reaction otherwise follows the same General and Highly Efficient Synthesis of 2-Alkylideneazetidines and Solution: (a, b) Write following conversions: Solution: This reaction is an example of electrophilic aromatic substitution. Why is NH2 group of aniline acetylated before carrying out nitration? Amongst the following, the strongest base in aqueous medium is . Which of the following reagents would not be a good choice for reducing an aryl nitro compound to an amine? Chem., 2011, Resonating Structure of Aniline. Match the reactions given in Column 1 with the statements given in Column II. Due to -I effect of CN group, NC-CH2NH2 is less basic than CH3NH2. (c) Fe and HCl     (d) Sn and HCl Solution: (a, b). Solution: Question 61. As a result, the activating effect -NH2 group is reduced i.e., the lone pair of electrons on nitrogen is less available for donation to benzene ring by resonance. The three types of amines can be distinguished by Hinsberg method. Solution: Nitrogen is less electronegative than oxygen, therefore, lone pair of electrons on nitrogen is readily available for donation. Predict the product of reaction of aniline with bromine in non-polar solvent such as CS 2. Write down the IUPAC name of Chem. (c) Assertion is correct but Reason is wrong. %PDF-1.4 substituted phenoxides) with aryl halides. endobj Diazotization :-The formation of diazonium salt from primary amine in a dilute mineral acid (HCl) and ... Chlorobenzene and bromobenzene respectively. Question 49. (viii) Aniline to chlorobenzene (ix) 2-Chlorobutane to 3, 4-dimethylhexane (x) ... the following reaction takes place: Give a mechanism for this reaction. J. Jiao, X.-R. Zhang, N.-H. Chang, J. Wang, J.-F. Wei, X.-Y. (a) NH3 > OH > NH3 > H2O (b) OH > NH2 > H2O > NH3 (a) CH3Br (b) C6H5Br (c) C6H5CH2Br (d) C2H5Br Catalysts Preference of 4-exo Ring Closure in Copper-Catalyzed Intramolecular Coupling Which of the following compounds is the weakest Bronsted base? Synlett, 2016, 27, 965-968. Explain the reactions involved. (c) 10 R – NH2 + RCHO followed by H2/Pt Solution: (c) 2° amine is more basic than 1° amine, i.e., (CH3)2NH is more basic than CH3NH2. 2002, 4, 581-584. J. Gao, S. Bhunia, K. Wang, L. Gan, S. Xia, D. Ma, Org. Solution: Coupling reaction of aryl diazonium chloride with aniline is carried out in mild acidic condition (pH = 4-5). As some The reagents that can be used to convert benzene diazonium chloride to Ligand for Copper-Catalyzed Cross-Coupling Reactions of Aryl Iodides with J. Niu, H. Zhou, Z. Li, J. Xu, S. Hu, J. Org. Identify compounds ‘A’ to ‘D’. Hence, (CH3)2NH has the highest basic strength as it has the highest reactivity. 137, 11942-11945. H.-J. (c) Heating alkyl halide with potassium salt of phthalimide followed by hydrolysis Solution: Question 15. %���� (b) 2° R – Br + NaCN followed by H2/Pt (a) CH3-0-N = 0 (b) CH3-0-CH3 Aniline or reaction with acetyl chloride or acetic anhydride in the presence of pyridine produces N-acetyl aniline which is a ortho, para directing group which on further reaction with nitrating mixture (cone. (d) Treatment of amide with bromine in aqueous solution of sodium hydroxide. The "classic" Ullmann Reaction is the synthesis of symmetric biaryls via copper-catalyzed coupling. The most reactive amine towards dilute hydrochloric acid is Assertion (A): Aromatic 1° amines can be prepared by Gabriel phthalimide synthesis. <>stream This method can also be used to Question 31. H2SO4 + cone. Predict the major product. Solution: (b) Aryl nitro compound cannot be converted into amine using LiAlH4 in ether. Since phenol is more acidic than alcohol, therefore, phenol (c) has the least tendency to accept a proton and hence it is the weakest Bronsted base. changing the number of carbon atoms in the chain is Can you suggest a method where RNH2 forms only 2° amine? R-NH2 + CHCl, + 3KOH -> RNC + 3KCl + 3H2O Only RNC and CHCl3 are involved in carbylamine reaction. In first step R – X bond is broken to produce a carbocation which is attacked by nucleophile. Amines Efficient and Reusable Catalyst for the Classic Ullmann Reaction Which of the following species are involved in the carbylamine test? HNO3 + cone. Question 5. 76, 1456-1459. Copper-Catalyzed Diaryl Ether Formation from (Hetero)aryl Halides at Low If you have any query regarding NCERT Exemplar Class 12 Chemistry Chapter 13 Amines, drop a comment below and we will get back to you at the earliest. In non-polar solvent (such as CS2) the activating effect of -NH2 group is reduced (due to resonance) and hence, mono substitution occurs only at o- and p-positions. Question 36.

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